A haemophilic man (XʰY) marries a woman who is homozygous normal (XᴴXᴴ). What will their children be?
Correct answer D. All daughters carriers and all sons normal
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Correct answer D. All daughters carriers and all sons normal
Correct answer B. 1/2
Correct answer A. an affected father through his carrier daughter to his grandson
Correct answer B. from a father to all of his sons
Correct answer A. 1 red : 2 pink : 1 white
Correct answer D. incomplete dominance
Correct answer A. 3/8
Correct answer A. Seven
Correct answer A. the garden pea, Pisum sativum
Correct answer A. separate so that each gamete receives only one allele
Correct answer C. homologous chromosomes during anaphase I of meiosis
Correct answer D. the random orientation of homologous pairs at metaphase I
Correct answer B. 3 : 1
Correct answer A. 1 : 2 : 1
Correct answer A. in a heterozygote one allele masks the expression of the other
Correct answer A. alleles
Correct answer D. a homozygous recessive individual
Correct answer B. 9 : 3 : 3 : 1
Correct answer D. 1 : 1 : 1 : 1
Correct answer A. 1/16