What is the angular momentum of an electron in the second Bohr orbit of hydrogen (h = 6.63 × 10⁻³⁴ J s)?
Correct answer C. 2.11 × 10⁻³⁴ J s
Explanation
Bohr's quantisation rule gives L = nh/2π. For n = 2, L = 2 × 6.63 × 10⁻³⁴/(2π) = h/π = 2.11 × 10⁻³⁴ J s.
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