Practice mode Atomic Spectra

What is the wavelength of the series limit of the Balmer series (R = 1.097 × 10⁷ m⁻¹)?

Correct answer B. 365 nm

Explanation

1/λ = R(1/2² − 0) = R/4, so λ = 4/R = 4/(1.097 × 10⁷) = 3.65 × 10⁻⁷ m = 365 nm.

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