What is the wavelength of the series limit of the Lyman series (R = 1.097 × 10⁷ m⁻¹)?
Correct answer D. 91.2 nm
Explanation
For the series limit n₂ = ∞, so 1/λ = R(1/1² − 0) = R. λ = 1/(1.097 × 10⁷) = 9.12 × 10⁻⁸ m = 91.2 nm.
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