What is the ratio of the wavelength of the first Lyman line (n = 2 to 1) to that of the first Balmer line (n = 3 to 2)?
Correct answer B. 0.185
Explanation
1/λ_L = R(1 − 1/4) = 3R/4 and 1/λ_B = R(1/4 − 1/9) = 5R/36. So λ_L/λ_B = (5/36)/(3/4) = 5/27 ≈ 0.185.
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