What is the wavelength of the first line of the Lyman series (n = 2 to n = 1) (R = 1.097 × 10⁷ m⁻¹)?
Correct answer A. 122 nm
Explanation
1/λ = R(1/1² − 1/2²) = 3R/4, so λ = 4/(3 × 1.097 × 10⁷) = 1.22 × 10⁻⁷ m ≈ 122 nm.
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