What mass of ethanoyl chloride (M = 78.5 g/mol) is formed from 0.25 mol of ethanoic acid with excess SOCl₂?
Correct answer A. 19.6 g
Explanation
CH₃COOH + SOCl₂ → CH₃COCl + SO₂ + HCl, a 1:1 ratio. So 0.25 mol of acid gives 0.25 mol ethanoyl chloride. Mass = 0.25 × 78.5 = 19.6 g.
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