12.0 g of ethanoic acid (M = 60 g/mol) reacts with excess ethanol to give 11.0 g of ethyl ethanoate (M = 88 g/mol). What is the percentage yield?
Correct answer C. 62.5%
Explanation
Moles of acid = 12.0/60 = 0.200 mol, so the theoretical mass of ester = 0.200 × 88 = 17.6 g. Percentage yield = (11.0/17.6) × 100 = 62.5%. Comparing 11.0 with 12.0 directly gives the wrong 91.7%.
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