A stone is projected at 20 m/s at 45° to the horizontal. Taking g = 10 m/s², what is its horizontal range?
Correct answer C. 40 m
Explanation
R = v₀² sin 2θ / g = (400 × sin 90°)/10 = 40 m. This is also the maximum range for a launch speed of 20 m/s.
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