A ball is thrown at 30 m/s at 30° above the horizontal. Taking g = 10 m/s², what is its time of flight?
Correct answer C. 3 s
Explanation
T = 2v₀ sin θ / g = (2 × 30 × 0.5)/10 = 3 s. Using only v₀ sin θ / g gives 1.5 s, which is the time to reach the highest point.
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