A ball is thrown horizontally at 15 m/s from the top of a 20 m high cliff. Taking g = 10 m/s², how far from the foot of the cliff does it land?
Correct answer D. 30 m
Explanation
Fall time from h = ½gt²: t = √(2 × 20/10) = 2 s. Horizontal distance = 15 × 2 = 30 m, since the horizontal velocity is unchanged.
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