A ball is projected at 20 m/s at 30° above the horizontal. Taking g = 10 m/s², what maximum height does it reach?
Correct answer D. 5 m
Explanation
H = v₀² sin²θ / 2g = (20² × 0.5²)/(2 × 10) = (400 × 0.25)/20 = 5 m. Forgetting to square sin θ gives 10 m.
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