What volume of CO₂ at STP is produced when 6.0 g of carbon burns completely in excess oxygen?
Correct answer D. 11.2 dm³
Explanation
C + O₂ → CO₂, so 6.0 g ÷ 12 g mol⁻¹ = 0.50 mol C gives 0.50 mol CO₂. Volume = 0.50 × 22.4 = 11.2 dm³.
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