For 2Al + 3Cl₂ → 2AlCl₃, 2.0 mol of Al is mixed with 2.0 mol of Cl₂. Which is limiting and how much AlCl₃ forms?

Correct answer B. Cl₂ is limiting; 1.33 mol AlCl₃

Explanation

2.0 mol Al needs 3.0 mol Cl₂, but only 2.0 mol is present, so Cl₂ is limiting. AlCl₃ = 2.0 × 2/3 = 1.33 mol.

Report a problem

Answer checked How we write and check questions

Tip: press A, B, C or D to answer, and N for the next question.

Advertisement

Have a question about this answer?

Your email address will not be published. Required fields are marked *

Links and website addresses are not allowed in comments.