For 2Al + 3Cl₂ → 2AlCl₃, 2.0 mol of Al is mixed with 2.0 mol of Cl₂. Which is limiting and how much AlCl₃ forms?
Correct answer B. Cl₂ is limiting; 1.33 mol AlCl₃
Explanation
2.0 mol Al needs 3.0 mol Cl₂, but only 2.0 mol is present, so Cl₂ is limiting. AlCl₃ = 2.0 × 2/3 = 1.33 mol.
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