In N₂ + 3H₂ → 2NH₃, 2.0 mol of N₂ reacts with 3.0 mol of H₂. What remains unreacted when the reaction is complete?
Correct answer C. 1.0 mol of N₂
Explanation
3.0 mol H₂ reacts with only 1.0 mol N₂, so H₂ is limiting. Excess N₂ left = 2.0 − 1.0 = 1.0 mol.
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