What mass of oxygen is needed to burn 8 g of methane completely (CH₄ + 2O₂ → CO₂ + 2H₂O)?
Correct answer A. 32 g
Explanation
Moles of CH₄ = 8 ÷ 16 = 0.5 mol. O₂ needed = 2 × 0.5 = 1.0 mol = 32 g. Ignoring the coefficient 2 gives 16 g.
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