6.0 g of H₂ reacts with excess N₂ (N₂ + 3H₂ → 2NH₃) and 25.5 g of NH₃ is obtained. What is the percentage yield?
Correct answer B. 75%
Explanation
H₂ = 3.0 mol, giving theoretical NH₃ = 2.0 mol = 34 g. Percentage yield = 25.5 ÷ 34 × 100 = 75%.
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