In a town, B is 10 m north of A. C is 6 m east of B. D is 2 m south of C. What is the shortest distance between D and A?
Correct answer D. 10 m
Explanation
Placing A at the origin, D is 6 m east and 8 m north of A. By Pythagoras the distance is the square root of (6² + 8²), which is 10 m.
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