What happens to round robin scheduling when the time quantum is made very large, longer than every CPU burst?
Correct answer D. It behaves the same as FCFS
Explanation
If the quantum exceeds every burst, no process is ever preempted, so each runs to the end of its burst in arrival order, which is exactly FCFS. A very small quantum causes the opposite problem: so many context switches that overhead dominates. A rule of thumb is that about 80 percent of CPU bursts should be shorter than the quantum.
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