In a centre-tapped full-wave rectifier, each half of the secondary winding has a peak voltage of 15 V. What peak inverse voltage must each ideal diode withstand?
Correct answer D. 30 V
Explanation
When one diode conducts, the non-conducting diode has the full secondary across it, which is twice the half-winding peak: PIV = 2 × 15 = 30 V.
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