A germanium diode (0.3 V drop) and a resistor are connected in series across a 9.0 V battery so that 20 mA flows in forward bias. What is the resistance?
Correct answer D. 435 Ω
Explanation
The resistor carries the supply voltage minus the diode drop: R = (V − V_diode)/I = (9.0 − 0.3)/0.020 = 8.7/0.020 = 435 Ω.
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