The flux through each turn of a 200-turn coil falls uniformly from 0.030 Wb to 0.010 Wb in 0.10 s. What is the magnitude of the induced emf?
Correct answer A. 40 V
Explanation
ε = NΔΦ/Δt = 200 × (0.030 − 0.010) ÷ 0.10 = 200 × 0.20 = 40 V. Ignoring the number of turns gives only 0.20 V.
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