A straight conductor 0.50 m long moves at 4.0 m/s at right angles to a uniform magnetic field of 0.30 T. What emf is induced between its ends?
Correct answer D. 0.60 V
Explanation
Motional emf ε = BLv = 0.30 T × 0.50 m × 4.0 m/s = 0.60 V. Dividing by v instead of multiplying gives 0.038 V.
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