A battery of emf 9.0 V has a terminal potential difference of 7.5 V when it delivers 1.5 A. What is its internal resistance?
Correct answer C. 1.0 Ω
Explanation
Lost volts = E − V = 9.0 − 7.5 = 1.5 V. Internal resistance r = 1.5 V ÷ 1.5 A = 1.0 Ω. The value 5.0 Ω is the external load resistance, V/I.
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