A battery of emf 12 V and internal resistance 0.50 Ω is connected to a 5.5 Ω resistor. What is the potential difference across the battery terminals?
Correct answer A. 11 V
Explanation
Current I = E/(R + r) = 12/(5.5 + 0.50) = 2.0 A. Terminal voltage V = IR = 2.0 × 5.5 = 11 V. The remaining 1.0 V is lost across the internal resistance.
Answer checked How we write and check questions
Discussion