A gas expands by 2.0 dm³ against a constant external pressure of 1.0 atm. What work is done on the gas (1 dm³ atm = 101.3 J)?
Correct answer D. −203 J
Explanation
w = −PΔV = −1.0 atm × 2.0 dm³ = −2.0 dm³ atm = −2.0 × 101.3 J ≈ −203 J. It is negative because the gas does work on the surroundings.
Answer checked How we write and check questions
Discussion