Neutralising 0.050 mol of HCl with excess NaOH releases 2.85 kJ of heat. What is the enthalpy of neutralisation?
Correct answer D. −57 kJ mol⁻¹
Explanation
ΔH per mole of water formed = −2.85 kJ ÷ 0.050 mol = −57 kJ mol⁻¹, negative because heat is released.
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