What volume does 3.2 g of oxygen gas, O₂, occupy at STP?
Correct answer B. 2.24 dm³
Explanation
Moles of O₂ = 3.2 g ÷ 32 g mol⁻¹ = 0.10 mol. Volume at STP = 0.10 × 22.4 dm³ = 2.24 dm³. Using 16 g mol⁻¹ wrongly gives 4.48 dm³.
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