How many sodium ions are present in 5.85 g of sodium chloride (Na = 23, Cl = 35.5)?
Correct answer D. 6.02 × 10²²
Explanation
5.85 g ÷ 58.5 g mol⁻¹ = 0.10 mol NaCl, which contains 0.10 mol Na⁺ ions, that is 0.10 × 6.02 × 10²³ = 6.02 × 10²² ions.
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