What mass of KClO₃ must be decomposed to give 9.6 g of oxygen (2KClO₃ → 2KCl + 3O₂; K = 39, Cl = 35.5, O = 16)?
Correct answer D. 24.5 g
Explanation
9.6 g of O₂ is 0.30 mol. From the 2 : 3 ratio, 0.20 mol of KClO₃ is needed, and 0.20 × 122.5 g mol⁻¹ = 24.5 g.
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