How many water molecules are present in 9.0 g of H₂O (H = 1, O = 16)?
Correct answer C. 3.01 × 10²³
Explanation
Moles of water = 9.0 g ÷ 18 g mol⁻¹ = 0.50 mol. Number of molecules = 0.50 × 6.02 × 10²³ = 3.01 × 10²³.
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