Heating 50 g of CaCO₃ gives 22.4 g of CaO (CaCO₃ → CaO + CO₂; Ca = 40, C = 12, O = 16). What is the percentage yield?
Correct answer C. 80%
Explanation
Theoretical CaO = 0.50 mol × 56 g mol⁻¹ = 28 g. Percentage yield = 22.4 ÷ 28 × 100 = 80%. Dividing 22.4 by 50 gives the wrong 44.8%.
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