Given E°(Zn²⁺/Zn) = −0.76 V and E°(Cu²⁺/Cu) = +0.34 V, what is the standard emf of the Daniell cell?
Correct answer B. 1.10 V
Explanation
E°cell = E°(cathode) − E°(anode) = +0.34 − (−0.76) = 1.10 V. Copper is the cathode because it has the higher reduction potential.
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