Given E°(Ag⁺/Ag) = +0.80 V and E°(Cu²⁺/Cu) = +0.34 V, what is E°cell for Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s)?
Correct answer D. 0.46 V
Explanation
E°cell = E°(cathode) − E°(anode) = 0.80 − 0.34 = 0.46 V. Electrode potentials are intensive, so the coefficient 2 for silver does not multiply E°.
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