A forward-biased silicon diode (0.7 V drop) is connected in series with a 430 Ω resistor across a 5.0 V supply. What current flows?
Correct answer B. 10 mA
Explanation
The diode takes 0.7 V, leaving the rest across the resistor: I = (V − V_diode)/R = (5.0 − 0.7)/430 = 4.3/430 = 0.010 A = 10 mA.
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