A bridge rectifier uses silicon diodes (0.7 V each) and its transformer secondary gives 12 V rms. What is the approximate peak output voltage across the load?
Correct answer B. 15.6 V
Explanation
Peak secondary voltage = 12 × √2 = 17.0 V. Two diodes conduct in series in a bridge, so subtract 2 × 0.7 = 1.4 V, giving about 15.6 V.
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