For H0: μ = 50 against H1: μ ≠ 50, a sample of 36 gives x̄ = 48 with σ = 6. At the 5% level, what is the conclusion?
Correct answer C. Reject H0 since |z| = 2 exceeds 1.96
Explanation
z = (48 − 50) / (6/6) = −2. Because |−2| is larger than the two-tailed critical value 1.96, the null hypothesis is rejected at 5%.
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