For 5 pairs of ranks, the sum of squared rank differences Σd² is 8. What is Spearman’s rank correlation coefficient?
Correct answer B. 0.6
Explanation
rs = 1 − 6Σd² / [n(n² − 1)] = 1 − 48 / (5 × 24) = 1 − 0.4 = 0.6.
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