If the glomerular filtration rate of an adult is 125 mL/min, what volume of filtrate is formed in one day?
Correct answer C. 180 L
Explanation
Volume per day = 125 mL/min × 60 min/h × 24 h = 180,000 mL = 180 L. Since only about 1.5 L of urine is passed, about 99% of the filtrate is reabsorbed.
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