In a population in Hardy-Weinberg equilibrium, 16% of individuals show a recessive phenotype. What is the frequency of heterozygotes?
Correct answer D. 0.48
Explanation
q² = 0.16, so q = 0.4 and p = 1 − 0.4 = 0.6. Heterozygote frequency = 2pq = 2 × 0.6 × 0.4 = 0.48.
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