A coil develops an induced emf of 2 V when the current through it changes at 4 A s⁻¹. What is its self-inductance?
Correct answer C. 0.5 H
Explanation
Self-inductance is the induced emf divided by the rate of change of current, so L = 2 V ÷ 4 A s⁻¹ = 0.5 H.
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