A 10 kg mass is whirled at 1 m/s on the end of an inextensible string 10 m long. What is the outward force on the mass?
Correct answer D. 1 N
Explanation
The required force is mv²/r = 10 × 1² ÷ 10 = 1 N, and the outward pull felt on the string has this same magnitude.
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