What is the escape velocity from the Earth’s surface in km s⁻¹?
Correct answer B. 11.2 km s⁻¹
Explanation
Using v = √(2gR) with g = 9.8 m/s² and R = 6.4 × 10⁶ m gives about 11.2 km/s, the minimum launch speed to leave the Earth without further propulsion.
Answer checked How we write and check questions
Discussion