An emf of 5 V is induced in a coil when the current changes steadily from 3 A to 2 A in 1 millisecond. What is the coil’s self-inductance?
Correct answer D. 5 mH
Explanation
Self-inductance is emf divided by rate of change of current. The current changes by 1 A in 0.001 s, so L = 5 ÷ 1000 = 0.005 H, or 5 mH.
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