An alternating current with an r.m.s. value of 4.0 A and frequency 50 Hz flows through a 10 Ω resistor. What is the peak current?
Correct answer A. 5.66 A
Explanation
For a sinusoidal current, I₀ = √2 × I_rms = 1.414 × 4.0 A ≈ 5.66 A. The resistance and frequency do not affect this ratio.
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