Practice mode Physics

A rubber cord 1 m long has a cross-sectional area of 2 cm². A tensile force of 10 N stretches it by 1 cm. What is the Young’s modulus of the rubber?

Correct answer A. 5 × 10⁶ N m⁻²

Explanation

Stress is 10 N ÷ 2 × 10⁻⁴ m² = 5 × 10⁴ N m⁻² and strain is 0.01, so Young's modulus = stress ÷ strain = 5 × 10⁶ N m⁻².

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