An uncharged 30 µF capacitor is charged by a constant current of 10 mA. How long does it take for the potential difference across it to reach 300 V?
Correct answer A. 0.9 s
Explanation
The charge needed is Q = CV = 30 × 10⁻⁶ × 300 = 9 × 10⁻³ C, and with constant current t = Q/I = 9 × 10⁻³ / 10⁻² = 0.9 s.
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