A man with blood group AB marries a woman who is heterozygous for blood group B. What is the probability that their first child will have blood group B?
Correct answer C. 50%
Explanation
The cross IAIB × IBi gives IAIB, IAi, IBIB and IBi in equal proportions. Both IBIB and IBi produce group B, so the chance is two in four, or 50 per cent.
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