Junction J2 of a thyristor has a capacitance CJ2 = 20 pF, assumed independent of off-state voltage. If a charging current of 16 mA turns the thyristor on, what is the critical dv/dt?
Correct answer B. 800 V/µs
Explanation
Charging current i = C dv/dt, so dv/dt = 16 × 10^-3 / 20 × 10^-12 = 8 × 10^8 V/s, which is 800 V/µs.
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