An SCR’s gate–cathode characteristic is a straight line with a slope of 130 (Vg/Ig = 130 Ω). With a trigger source of 15 V and an allowable gate power dissipation of 0.5 W, what gate source resistance is required?
Correct answer B. 111.9 Ω
Explanation
Pg = 130 Ig² = 0.5 W gives Ig ≈ 0.062 A and Vg ≈ 8.06 V. The source resistance is (15 − 8.06)/0.062 ≈ 111.9 Ω.
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